Weather Satellites and Orbits
Problems and Solutions
Newton's Law of Gravity
(1) Calculate the altitude at which a satellite of mass 2105 kg orbits the Earth. The gravitational force is 649 N and the universal constant of gravitation G is 6.673*10-11 N*m2/kg2. The mass of the Earth is 5.988*1024 kg. Solution
(2) Calculate the altitude at which a satellite of mass 2100 kg orbits a planet of mass 2.736*1023 kg. The gravitational force is 450 N and the universal constant of gravitation G is 6.673*10-11 N*m2/kg2. Solution
SOLUTIONS
(1) Altitude is 36,000 km
HOW TO SOLVE THIS PROBLEM:
G = Universal constant of gravitation = 6.673*10-11 N*m2/kg2
m1 = mass of planet = 5.99*1024 kg
m2 = mass of satellite = 2105 kg
F = gravitational force = 649 N
r = altitude of satellite = ?
F= (G*m1*m2)/r2
r2= (G*m1*m2)/F
r= ((G*m1*m2)/F)1/2
r= (((6.673*10-11 N*m2/kg2)*(5.988*1024 kg)*2105 kg)/649 N)1/2
r= 3.6*107 m
r= 36,000 km
(2) Altitude is 9230 km
HOW TO SOLVE THIS PROBLEM:
G = Universal constant of gravitation = 6.673*10-11 N*m2/kg2
m1 = mass of planet = 2.736*1023 kg
m2 = mass of satellite = 2100 kg
F = gravitational force = 450 N
r = altitude of satellite = ?
F= (G*m1*m2)/r2
r2= (G*m1*m2)/F
r= ((G*m1*m2)/F)1/2
r= (((6.673*10-11 N*m2/kg2)*(2.736*1023 kg)*2100 kg)/450 N)1/2
r= 9.2*106 m
r= 9200 km
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